The checkPassword function in python-kerberos does not authenticate the KDC it attempts to communicate with, which allows remote attackers to cause a denial of service (bad response), or have other unspecified impact by performing a man-in-the-middle attack.
원문출처 : https://web.nvd.nist.gov/view/vuln/detail?vulnId=CVE-2015-3206
원문출처 : https://web.nvd.nist.gov/view/vuln/detail?vulnId=CVE-2015-3206
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| 번호 | 제목 | 글쓴이 | 날짜 | 조회 수 |
|---|---|---|---|---|
| 467 | CVE-2017-9650 | 관리자 | 2017.08.27 | 18 |
| 466 | CVE-2016-3220 | 관리자 | 2016.06.17 | 18 |
| 465 | CVE-2016-3210 | 관리자 | 2016.06.17 | 18 |
| 464 | CVE-2017-2742 | 관리자 | 2018.01.25 | 17 |
| 463 | CVE-2018-1000011 | 관리자 | 2018.01.25 | 17 |
| 462 | CVE-2017-17406 | 관리자 | 2018.01.25 | 17 |
| 461 | CVE-2017-12119 | 관리자 | 2018.01.25 | 17 |
| 460 | CVE-2017-14119 | 관리자 | 2017.09.04 | 17 |
| 459 | CVE-2017-14116 | 관리자 | 2017.09.04 | 17 |
| 458 | CVE-2017-15105 | 관리자 | 2018.01.25 | 16 |
| 457 | CVE-2017-15091 | 관리자 | 2018.01.25 | 16 |
| 456 | CVE-2018-1000012 | 관리자 | 2018.01.25 | 16 |
| 455 | CVE-2018-1000016 | 관리자 | 2018.01.25 | 16 |
| 454 | CVE-2018-1000008 | 관리자 | 2018.01.25 | 16 |
| 453 | CVE-2018-1042 | 관리자 | 2018.01.25 | 16 |